Difference between revisions of "Passing UDTs to Classes"
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| − | <b>NOTE: </b>This will only work when using the class from within the same project in VB. If compiled and used as a COM component, then any methods declared as 'Friend' will not appear. See MSDN on the topic of the Friend keyword: http://msdn.microsoft.com/library/default.asp?url=/library/en-us/vbenlr98/html/vakeyFriend.asp | + | <b>NOTE: </b>This will only work when using the class from within the same project in VB. If compiled and used as a COM component, then any methods declared as 'Friend' will not appear. See MSDN on the topic of the Friend keyword:<br>http://msdn.microsoft.com/library/default.asp?url=/library/en-us/vbenlr98/html/vakeyFriend.asp |
Revision as of 13:07, 2 September 2005
This is actually extremely simple to do - all you need to do is declare the method (be it a property, function or sub) to which you are passing the UDT as Friend - like this:
'-- In some module
Public Type myType
x As Integer
y As Integer
End Type
'-- In the class
Friend Function myFunction(foo As myType) As Integer
myFunction = foo.x + foo.y
End Function
'-- Passing to the function
Dim foo As myType
foo.x = 10: foo.y = 100
Debug.Print myClassInstance.myFunction(foo) '-- Prints 1000 to Immediate window
Simple :-)
NOTE: This will only work when using the class from within the same project in VB. If compiled and used as a COM component, then any methods declared as 'Friend' will not appear. See MSDN on the topic of the Friend keyword:
http://msdn.microsoft.com/library/default.asp?url=/library/en-us/vbenlr98/html/vakeyFriend.asp
